=begin

If the numbers 1 to 5 are written out in words: one, two, three, four, five; there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total.

If all the numbers from 1 to 1000 (one thousand) inclusive were written out in words, how many letters would be used?
NOTE: Do not count spaces or hyphens. For example, 342 (three hundred and forty-two) contains 23 letters and 115 (one hundred and fifteen) contains 20 letters.

=end

upbound = 1000

words = {1=>'one',2=>'two',3=>'three',4=>'four',5=>'five',6=>'six',7=>'seven',8=>'eight',9=>'nine',10=>'ten',11=>'eleven',12=>'twelve',13=>'thirteen',14=>'fourteen',15=>'fifteen',16=>'sixteen',17=>'seventeen',18=>'eighteen',19=>'nineteen',0=>''}

tenwords = {2=>'twenty',3=>'thirty',4=>'forty',5=>'fifty',6=>'sixty',7=>'seventy',8=>'eighty',9=>'ninety'}

sum = 0
1.upto upbound do |n|
  word = '' #lbotest
  n = n.to_s
  skip = false
  if n.length > 2 && !n.match(/^[123456789]{1}[0]+$/)
    word += 'and' #lbotest
  end
  1.upto n.length do |i|
    if skip
      skip = false
      next
    end
    if i == 1
      if n.length >= 2
        tens = n[-2,2].to_i
        if !words[tens].nil?
          word += words[tens] #lbotest
          skip = true
          next
        end
      end
      word += words[n[-1,1].to_i] #lbotest
    elsif i == 2
      word += tenwords[n[-2,1].to_i] #lbotest
    elsif i == 3 && n[-3,1] != '0'
      word += words[n[-3,1].to_i] #lbotest
      word += 'hundred' #lbotest
    elsif i == 4
      word += words[n[-4,1].to_i] #lbotest
      word += 'thousand' #lbotest
    end
  end
  sum += word.length
  print(word+' '+word.length.to_s+"\n")
end

print(sum)